Let $A, B$ be the bases of $W, V$ respectively. then in the vector space V, A is linearly independent, B spans V, so $\text{rank}(A) \le \text{rank}(B)$, thus completes the proof of the first part.

The second part is also straight forward. If B is a basis of V and rank(A) = rank(B), then A is also a basis of V. (review the above link.)

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